m^2
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Find the dimensions of the garden. Found 3 solutions by jorel555, ankor@dixie-net.com, Alan3354:Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let w be the width of the garden. Then the length is w+5. So:
w(w+5)=66
w²+5w-66=0
(w+11)(w-6)=0
w=-11 or 6
The positive value for the width is 6m. Then the length is 11m. ☺☺☺☺
You can put this solution on YOUR website! The length of a rectangular garden is 5 m greater than the width.
L = (w+5)
:
The area is 66 m^2
L * w = 66
Replace L with (w+5)
(w+5) * w
w^2 + 5w = 66
a quadratic equation
w^2 + 5w - 66 = 0
Factors
(w+11)(w-6) = 0
the positive solution
w = 6 m
You find the length, then find the area.
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m^2
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Find the dimensions of the garden.
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find a pair of factors of 66 that differ by 5.
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You can make some equations first, then when you factor the quadratic, you have to find a pair of factors of 66 that differ by 5.
Why go around the barn?
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If the dimensions are not integers, then you have to go the long way around, but check for an integer solution first.
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