SOLUTION: For the following problem, the slope and one point on a line is given. Use the point-slope form to find the equation of that line. (Write your answer in slope-intercept form.) (3,

Algebra ->  Linear-equations -> SOLUTION: For the following problem, the slope and one point on a line is given. Use the point-slope form to find the equation of that line. (Write your answer in slope-intercept form.) (3,      Log On


   

Question 1060847: For the following problem, the slope and one point on a line is given. Use the point-slope form to find the equation of that line. (Write your answer in slope-intercept form.)
(3,−5), m = 0
Find the slope of a line parallel to the line that crosses (3,−4) and the y-intercept is (0,2).

Solve the following equation using the four steps.
−4(5t−1)=2(3−10t)−2
Please help me. These all confuse me :(
Found 2 solutions by Fombitz, addingup:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the point slope form,
y-y%5B0%5D=m%28x-x%5B0%5D%29
y-%28-5%29=0%28x-3%29
y%2B5=0
y=-5
.
.
.
So the line would have the form,
y=mx%2B2
So plug in the point to find m,
-4=m%283%29%2B2
3m=-6
m=-2
.
.
.
-4%285t-1%29=2%283-10t%29-2
-20t%2B4=6-20t-2
-20t%2B4=-20t%2B4
0=0
True, this is an identity.

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
find the slope of the line that goes through the ordered pair (3,-4)(0,2):
Slope is rise/run = (change in y)/(change in x). The slope is called m, so:
m = (y_2-y_1)/(x_2-x_1) = (2-(-4))/(0-3) = -2
Now we have the value of m: -2.
Next:
Determine the equation of the line that has the point (0,2) on it and the slope of the line m = -2.
We have:
y = mx+b
2 = -2(0)+b
2+2(0) = b
b = 2
y = mx+b is equal to 2 = -2(0)+2
So now we write our findings in slope-intercept form:
y = -2x+2
And we're done.