SOLUTION: A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid. How much of each must he use to make 80 grams of a 15% boric acid solution
Question 1060753: A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid. How much of each must he use to make 80 grams of a 15% boric acid solution Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid.
How much of each must he use to make 80 grams of a 15% boric acid solution.
:
let x = amt of 20% solution required
the resulting amt is to be 80 grams therefore
(80-x) = amt of 12% solution needed
:
A decimal equiv of per cent equation
.20x = .12(80-x) = .15(80)
.20x + 9.6 - .12x = 12
.20x - .12x = 12 - 9.6
.08x = 2.4
x = 2.4/.08
x = 30 grams of the 20% solution
and obviously
80 - 30 = 50 grams of the 12%
;
;
Check
.20(30) + .12(50) = .15(80)
6 + 6 = 12
