SOLUTION: Find the value of k so that the line through the given points has slope m.
(k+1, 3+2k), (k-1, 1-k); m=k
I've got to k=((1-k)-(3+2k))/((k-1)-(k+1))
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-> SOLUTION: Find the value of k so that the line through the given points has slope m.
(k+1, 3+2k), (k-1, 1-k); m=k
I've got to k=((1-k)-(3+2k))/((k-1)-(k+1))
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Question 106059This question is from textbook
: Find the value of k so that the line through the given points has slope m.
(k+1, 3+2k), (k-1, 1-k); m=k
I've got to k=((1-k)-(3+2k))/((k-1)-(k+1)) This question is from textbook
You can put this solution on YOUR website! Find the value of k so that the line through the given points has slope m.
(k+1, 3+2k), (k-1, 1-k); m=k
I've got to m=[(1-k)-(3+2k))]/[(k-1)-(k+1)]
m = [-2-3k]/[-2]
m = (2+3k)/2
Cheers,
Stan H.
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