SOLUTION: A block of stone weighs 217 lbs. with the dimensions 20 in. in length, 15 in. in width, and 8 in. in thickness. Determine dimensions of another block weighing 13888 lbs. Length

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Question 1060446: A block of stone weighs 217 lbs. with the dimensions 20 in. in length, 15 in. in width, and 8 in. in thickness. Determine dimensions of another block weighing 13888 lbs.
Length * width * thickness = volume.
Unsure how to continue. Thanks.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39627) About Me  (Show Source):
You can put this solution on YOUR website!
"Another block", how? Are the two blocks supposed to be similar? Assuming that they are ,
and also expect that the density of the two blocks will be equal.

volume is directly proportional to mass.



k is a factor applied to each dimension. Solve for k in the equation and then find each of the three dimensions using k.

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!
A block of stone weighs 217 lbs. with the dimensions 20 in. in length, 15 in. in width, and 8 in. in thickness. Determine dimensions of another block weighing 13888 lbs.
Length * width * thickness = volume.
Unsure how to continue. Thanks.
Larger block's volume (13,888 lbs) is 64 times smaller block's volume (217 lbs)
Hence, the blocks being 3-dimensional, we find the cube root of 64, which is 4
This means that each dimension should be multiplied by 4, thus giving us the following:
That's all.......nothing COMPLEX!!