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Question 1060225: Tyler has two savings accounts that his grandparents opened for him. One of the accounts pay 7% annual interest, whereas the other pays 9% annual interest. If you have $300 more invested at 9% than you invested at 7%, how much do you have invested in each account if the total amount of interest you earn in a year is $107?
Perform the following additions and/or subtractions:
(5q3−8q2−1)−(−5q3+8q2+1)
Please help me. im so confused with these problems :(
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Tyler has two savings accounts that his grandparents opened for him. One of the accounts pay 7% annual interest, whereas the other pays 9% annual interest. If you have $300 more invested at 9% than you invested at 7%, how much do you have invested in each account if the total amount of interest you earn in a year is $107?
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A = total amount invested at 7%
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Interest = 0.07*A + 0.09*(A + 300) = 107
0.07A + 0.09A + 27 = 107
0.16A = 80
A = 80/0.16 = $500
--> $500 @ 7% and $800 @ 9%
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Perform the following additions and/or subtractions:
Use ^ (Shift 6) for exponents.
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(5q^3 - 8q^2 - 1) - (-5q^3 + 8q^2 + 1)
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Change all the signs in the 2nd trinomial and add them.
(5q^3 - 8q^2 - 1) + (5q^3 - 8q^2 - 1)
Combine like terms, ie, q^3 terms, q^2 terms, etc
= 10q^3 - 16q^2 - 2
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