SOLUTION: Find an equation of the circle that has center (-4,3) and passes through (-6,-4)

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Question 1060148: Find an equation of the circle that has center (-4,3) and passes through (-6,-4)
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Using the formula:
(x - a)^2 + (y - b)^2 = r^2
Find radius by distance formula:
using centre coordinates (-4,3) and (-6, -4)
√ (x2 - x1)^2 + (y2 - y1)^2
√ (-6 - (-4))^2 + (-4 - 3)^2
√ (-6 + 4)^2 + (-7)^2
√ (-2)^2 + (-7)^2
√ 4 + 49
Radius - √53
(x - a)^2 + (y - b)^2 = r^2
(x - (-4))^2 + (y - 3)^2 = (√53)^2
(x + 4)^2 + (y - 3)^2 = 53
x^2 + y^2 + 8x - 6y - 28 = 0
Hope this helps :-)