SOLUTION: The sides of a rectangular floor are x m and (x+7).the diagonal is (x+8).calculate
I:the value of x
ii:the area of the floor
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-> SOLUTION: The sides of a rectangular floor are x m and (x+7).the diagonal is (x+8).calculate
I:the value of x
ii:the area of the floor
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Question 1060134: The sides of a rectangular floor are x m and (x+7).the diagonal is (x+8).calculate
I:the value of x
ii:the area of the floor Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
Using Pythagoras Theorem
x^2 + (x + 7)^2 = (x + 8)^2
x^2 + x^2 + 14x + 49 = x^2 + 16x + 64
Collect like terms:
x^2 + x^2 - x^2 + 14x - 16x + 49 - 64 = 0
x^2 - 2x - 15 = 0
Factorise
(x + 3)(x - 5) = 0
x + 3 = 0
x = -3 (Disregard as -ve value)
x - 5 = 0
x = 5.
Area of floor will be x(x + 7)
= 5(5 + 7)
= 60 m^2
Hope this helps :-)
