SOLUTION: The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR
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Question 1060124: The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR Found 3 solutions by Fombitz, ikleyn, MathTherapy:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! So R would be the midpoint of PQ.
The midpoint is the average of the x and y values,
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Q:(,)
You can put this solution on YOUR website! .
The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR
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The points in the y-axis are {R = (0,y)}.
The distance from R to P is = .
The distance from R to Q is = .
The condition |PR| = |QR| is
= .
Square both sides to get
9 + (y-7)^2 = 121+(y+6)^2.
9 + y^2 - 14y + 49 = 121 + y^2 + 12y + 36,
-99 = 26y.
y = .
You can put this solution on YOUR website! The co ordinates of the end points of a line segment PQ are P(3,7) and Q(11,-6). Find the coordinates of the point R on the y-axis such that PR=QR
Fact: The given points are located in the 1st and 4th quadrants
Fact: The x-coordinate of R is 0
y coordinate, when found, is: , so coordinates of R are:
