SOLUTION: HELP ME PLS A nozzle which is attached to the end of a 4-in fire hose has a length of 1 ft and a diameter at the discharge end of 1 in. If it has a uniform thickness of 5/16 in

Algebra ->  Volume -> SOLUTION: HELP ME PLS A nozzle which is attached to the end of a 4-in fire hose has a length of 1 ft and a diameter at the discharge end of 1 in. If it has a uniform thickness of 5/16 in       Log On


   

Question 1059972: HELP ME PLS
A nozzle which is attached to the end of a 4-in fire hose has a length of 1 ft and a diameter at the discharge end of 1 in. If it has a uniform thickness of 5/16 in and is made of brass, find the weight of material used in the manufacture of 1000 such nozzles. (Brass weighs 520 lb per cu. ft)
Found 2 solutions by Alan3354, blaser211:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A nozzle which is attached to the end of a 4-in fire hose has a length of 1 ft and a diameter at the discharge end of 1 in. If it has a uniform thickness of 5/16 in and is made of brass, find the weight of material used in the manufacture of 1000 such nozzles. (Brass weighs 520 lb per cu. ft)
--------
Some details are missing.
---
Assuming it's 2 concentric cones, and that the ID of the end on the hose is 4 inches:
--> 2 frustums (frusta?) of cones.
For the outside cone:
R = large end radius, r = small end radius
R = 2.3125, r = 0.8125 inches
----
Vol of the frustum = %28pi%2Ah%2F3%29%2A%28R%5E2+%2B+R%2Ar+%2B+r%5E2%29
= 4pi%2A%282.3125%5E2+%2B+2.3125%2A0.8125+%2B+0.8125%5E2%29
= 4pi%2A7.8867 =~ 99.1074 cu inches
------
Subtract the volume of the inside frustum:
Vol = 4pi%2A%282%5E2+%2B+2%2A0.5+%2B+0.5%5E2%29
= 4pi*5.25 = 21pi =~ 65.973 cu inches
-----
33.134 cu inches
======================
1 cu ft = 1728 cu inches
Weight = (33.134/1728)*520
=~ 9.97 pounds
x1000 = 9970 pounds (with no scrap)

Answer by blaser211(6) About Me  (Show Source):
You can put this solution on YOUR website!
sir the answer in our book is 997.08 lb.
i dont get how to get it