SOLUTION: Determine four consecutive integers such that the sum of the first three integers is 20 more than the fourth integer

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Question 1059969: Determine four consecutive integers such that the sum of the first three integers is 20 more than the fourth integer
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine four consecutive integers such that the sum of the first three integers is 20 more than the fourth integer
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1st:: x-2
2nd:: x-1
3rd:: x
4th:: x+1
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Equation:
3x-3 = (x+1)+20
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2x = 24
x = 12
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1st:: x-2 = 10
2nd:: 11
3rd:: 12
4th:: 13
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Cheers,
Stan H.
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Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Determine four consecutive integers such that the sum of the first three integers is 20 more than the fourth integer
Let the smallest integer be S

Then the others are: S + 1, S + 2, and S + 3

Equation needed: S + S + 1 + S + 2 = S + 3 + 20

Solve for S, the smallest

Count by 1s after to get the other 3, or add to the preceding to get the next larger