SOLUTION: Solve secΘ = -2 for all Θ such that 0° ≤ Θ ≤ 360°. Round you answers to the nearest degree

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Question 1059904: Solve secΘ = -2 for all Θ such that 0° ≤ Θ ≤ 360°. Round you answers to the nearest degree
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
secant is 1/cos
Need cosine - 1/2. That is in the second and third quadrants.
That is at 120 degrees or pi/3 and minus 120 degrees, or 240 degrees (2 pi/3).