SOLUTION: The product of two consecutive integers is 25 less than five times their sum. find the integers give your answer as comma separated numbers in acending order.

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Question 1059834: The product of two consecutive integers is 25 less than five times their sum. find the integers give your answer
as comma separated numbers in acending order.

Answer by ikleyn(52909) About Me  (Show Source):
You can put this solution on YOUR website!
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The product of two consecutive integers is 25 less than five times their sum. find the integers give your answer as
comma separated numbers in highlight%28cross%28acending%29%29 ascending order.
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Let the smaller number be "n".
Then the larger is (n+1), and the condition says

n*(n+1) = 5*(n+(n+1)) - 25.

Simplify:

n%5E2+%2B+n = 5*(2n+1) - 25,

n%5E2+%2B+n = 10n +5 - 25,

n%5E2+-9n++%2B+20 = 0.

Factor

(n-4)*(n-5) = 0.

This equation has two roots n=4 and n=5.

Answer. There are two solutions and two pairs of such consecutive integers: (4,5) and (5,6).