SOLUTION: log(2/3,x) + [log(3/2,x)]^-1= log(x,4/9)^2
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Question 1059774
:
log(2/3,x) + [log(3/2,x)]^-1= log(x,4/9)^2
Answer by
Alan3354(69443)
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log(2/3,x) + [log(3/2,x)]^-1= log(x,4/9)^2
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Is the 1st term the base?
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eg,
?