SOLUTION: The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width. What are the dimensions of the frame?

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width. What are the dimensions of the frame?      Log On


   



Question 1059741: The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width. What are the dimensions of the frame?
Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width.
What are the dimensions of the frame?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let L be the length, W be the width.
Then the condition says:

L = 2W - 3.

The perimeter is L + W + L + W.

Substitute (2W-3) instead of L in the perimeter.

You will get for the perimeter this expression: (2W-3) + W + (2W-3) + W.

Or, combining the like terms, 6W - 6.

It is equal to 30, according to the condition:

6W - 6 = 30.

Then 6W = 30 + 6,

6W = 36,

W = 6 inches.

So, you just found the width. It is 6 inches.

Now, the length is 2W -3 = 2*6-3 = 9 inches.