Question 1059680: Find the area of a parallelogram with vertices (0, 0), (3, 3), (4, 6), and (7, 9)
Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113)   (Show Source):
You can put this solution on YOUR website! Shoelace Theorem:
0.....0
3.....3
4.....6
7.....9
0.....0
left column to right column: (0*3) + (3*6) + (4*9) + (7*0) = 54
right column to left column: (0*3) + (3*4) + (6*7) + (9*0) = 54
area = 1/2 * |54 - 54| = 0
Answer by ikleyn(52787)  (Show Source):
You can put this solution on YOUR website! .
It is clear from the first glance that the answer/(the solution) by @Penguin is not correct.
It is seen from the fact that the four given points are not collinear.
So, the solution by @Penguin is wrong.
Where the mistake is ?
--- The mistake is in incorrect using the Shoelace theorem.
To apply this formula, the vertices must be listen in the clockwise (or anti-clockwise) order.
In this case, @Penguin failed to apply the formula correctly - it is the mistake' source.
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