Question 1059298: I need help on this please, it might be simple to you but to me its hard!
Tori has 8 coins, all of which are quarters and nickels. In all, they're worth $1.40. How many of each kind of coin does Tori have?
Found 2 solutions by addingup, ikleyn:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Don't despair, no one I know was born knowing math. Maybe Einstein, but I never met the guy... before my time ;-)
:
Tori has: q+n = 8 That's 2 variables, q and n. Too many, let's make it just one variable: Tori has q+n = 8, subtract q on both sides and we get:
q-q+n = 8-q; n = 8-q (always do to one side what you do to the other)
:
Next:
0.25q+0.10n = 1.40 substitute for n, like this:
0.25q+0.10(8-q) = 1.40
0.25q+0.80-0.10q = 1.40 simplify q on left and subtract 0.80 on both sides:
0.15q = 0.60 divide both sides by 0.15:
q = 4 Tori has 4 quarters and 8-4= 4 dimes
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Check:
4*0.25 = 1
4*0.10 = 0.40
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Total . .1.40 Correct
Answer by ikleyn(53765)  (Show Source):
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