Question 1059194: There are four consecutive even integers. Two times the first plus the third equals 16. What is the sum of the four integers?
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website!
I find its often best to keep the number of variables to a minimum, so let's set the first number to n then relate all the others to n, to the extent possible:
—
Let n = first integer
n+2 = 2nd
n+4 = 3rd
n+6 = 4th
—
Two times first plus 3rd equals 16:
2(n) + (n+4) = 16
—
We just need to solve for n and we're done!
2n + n + 4 = 16
3n + 4 = 16
3n = 12
3n/3 = 12/3
n = 4
—
Ans: The four numbers are 4, 6, 8, and 10
—
Check:
Does 2(4) + 8 = 16? yes it does.
—
|
|
|
