SOLUTION: Need help evaluating this expression. tan(90 - ⊖) *tan(⊖)*sec(⊖) A.) {{{ 1 }}} B.) {{{ 2 }}} C.) sec{⊖) D.) cot(⊖) Thanks.

Algebra ->  Testmodule -> SOLUTION: Need help evaluating this expression. tan(90 - ⊖) *tan(⊖)*sec(⊖) A.) {{{ 1 }}} B.) {{{ 2 }}} C.) sec{⊖) D.) cot(⊖) Thanks.      Log On


   



Question 1059154: Need help evaluating this expression.
tan(90 - ⊖) *tan(⊖)*sec(⊖)
A.) +1+
B.) +2+
C.) sec{⊖)
D.) cot(⊖)
Thanks.

Answer by solve_for_x(190) About Me  (Show Source):
You can put this solution on YOUR website!
Since tan(x) = sin(x) / cos(x), and sin(90 - x) = cos(x), and cos(90 - x) = sin(x), the
first term of the expression can be rewritten as:

tan(90 - ⊖) = sin(90 - ⊖)/cos(90 - ⊖) = cos(⊖)/sin(⊖)

Substituting this in place of tan(90 - ⊖) then gives:

%28cos%28theta%29%2Fsin%28theta%29%29+%2A+tan%28theta%29+%2A+sec%28theta%29

=

= sec(⊖)