SOLUTION: sin^2(θ) = 7 − 2 cos^2(θ)

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Question 1059042: sin^2(θ) = 7 − 2 cos^2(θ)
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sin^2(θ) = 7 − 2 cos^2(θ)
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1-cos^2(t) = 7 - 2cos^2(t)
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cos^2(t) = 6
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cos(t) = sqrt(6)
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There is no angle whose cos = sqrt(6)
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Ans:: No solution
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
This problem doesn't make sense to me.
Both sin and cos have to be some value
between +0+ and +1+
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there is no way to make the equation work
Say +theta+=+90+ degrees. I get:
+1+=+7+-+2%2A0+
+1+=+7+
Did you copy this right?