SOLUTION: Find the rule of the quadratic function whose graph has its vertex at (-3, -2) and passes through (4, 145). f(x)=

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Question 1059031: Find the rule of the quadratic function whose graph has its vertex at (-3, -2) and passes through (4, 145).
f(x)=
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39615) About Me  (Show Source):
Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Find the rule of the quadratic function whose graph has its vertex at (-3, -2) and passes through (4, 145).
f(x)=
The quadratic function is: highlight_green%28f%28x%29+=+3%28x+%2B+3%29%5E2+-+2%29

PAY NO ATTENTION to anyone who tells you otherwise.

Answer by ikleyn(52770) About Me  (Show Source):
You can put this solution on YOUR website!
.
The solution by "josgarithmetic"    My comments       Right solution


y=a%28x-%28-3%29%29%5E2-2                     Correct.      


y=a%28x%2B3%29%5E2-2                        Correct.


a%28x%2B3%29%5E2=2-y                        Wrong.           a%28x%2B3%29%5E2 = 2+y. 


a=%282-y%29%2F%28x%2B3%29%5E2                            Wrong.           a = %282%2By%29%2F%28x%2B3%29%5E2.


a=%282-145%29%2F%284%2B3%29%5E2                           Wrong.           a = %282%2B145%29%2F%284%2B3%29%5E2.


a=%28-143%29%2F49                            Wrong.           a = %28147%29%2F49 = 3.


y=-%28143%2F49%29%28x%2B3%29%5E2-2                 Wrong.           y = 3%2A%28x%2B3%29%5E2-2.