Find three even consecutive integers such that the sum of the first two exceeds the third by 16
Let smallest integer be S
Then others are: S + 2, and S + 4
Therefore, S + S + 2 = S + 4 + 16
Solve this for S, the smallest integer
Add 2 to S to get middle integer
Add 4 to S to get largest, OR
Just count by 2s after getting the smallest, to get middle and largest.