SOLUTION: Ten students will split up into two groups of five to be put into two cars to travel to an academic meet. Two of the people, Billy and Willy, always travel in the same car. How man
Algebra ->
Permutations
-> SOLUTION: Ten students will split up into two groups of five to be put into two cars to travel to an academic meet. Two of the people, Billy and Willy, always travel in the same car. How man
Log On
Question 1059002: Ten students will split up into two groups of five to be put into two cars to travel to an academic meet. Two of the people, Billy and Willy, always travel in the same car. How many different ways can the students be grouped together to ride in the cars? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Ten students will split up into two groups of five to be put into two cars to travel to an academic meet. Two of the people, Billy and Willy, always travel in the same car. How many different ways can the students be grouped together to ride in the cars?
--------------
# of ways to place Billy and Willy:: 2
# of ways to pick 3 more for B&W's car:: 8C3 = (8*7*6)/(1*2*3) = 56
# of ways to fill the 2nd car with 5:: 5C5 = 1
-----
Ans: 2*56 = 112 ways
----------
Cheers,
Stan H.
-------------