SOLUTION: 5/cubed root of (5x)^2

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Question 10590: 5/cubed root of (5x)^2
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
5%2F%28root%283%2C+25x%5E2%29%29

In order to make this denominator into a perfect cube, you will have to get it UP to 125x%5E3. In order to do this, you'll have to multiply numerator and denominator by +root%283%2C+5x%29.

It should look like this:



+%285%2Aroot%283%2C5x%29%29%2F+%28root%283%2C+125x%5E3%29%29+

+%285+%2A+root%283%2C5x%29%29+%2F+%285x%29+

This reduces to:
+%28root%283%2C5x%29%29%2F+x

R^2 at SCC