SOLUTION: A shirt costs rupees 12 more than a belt.The total cost of a 2 such shirts and 5 such belts was rupees 164.What was the cos of a belt.

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Question 1058986: A shirt costs rupees 12 more than a belt.The total cost of a 2 such shirts and 5 such belts was rupees 164.What was the cos of a belt.
Answer by ikleyn(52807) About Me  (Show Source):
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A shirt costs rupees 12 more than a belt.The total cost of a 2 such shirts and 5 such belts was rupees 164.What was the cos of a belt.
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 S -  B =  12,     (1)   ("A shirt costs rupees 12 more than a belt.")
2S + 5B = 164.     (2)   ("The total cost of a 2 such shirts and 5 such belts was rupees 164.")


To solve the system, multiply the equation (1) by 5 (both sides) and add to the equation (2). You will get

5S + 2S = 60 + 164,

7S = 224  --->  S = 224%2F7 = 32.

Can you complete the solution from this point on your own?