SOLUTION: Theresas five test grades for this semester are 86% 78% 68% 92% and 72% her final exam counts one third of her final grade what range of grades on her final exam results and Teres

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Question 1058965: Theresas five test grades for this semester are 86% 78% 68% 92% and 72% her final exam counts one third of her final grade what range of grades on her final exam results and Teresa receiving a final grade of B in the course for Teresa to obtain a B in this course her average messed be greater than or equal to 80 but less than 90.
86+78+68+92+72 = 396
396÷5 = 79 .2
1/3×79.2 equals 79.2÷3 equals 26.4
I am unsure if I'm on the right track or what my next step would be.
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
86, 78, 68, 92, 72 are two-thirds of the course grade and some unknown T is worth one third of the course grade. Based on each normal test is 100 percentage points, 5%2A100=500 is 2%2F3 of the course and T is 1%2F3 of the course. Trying to think as practically as you can, half of the 500 percentage points is 250 percentage points, which is ONE THIRD of the course grade. Total percentage points for the course is 500%2B250=750.

Reread a few times if needed until you understand that.

Theresa needs average 80 to 90 percent for grade of B. What should score T be?


80%3C%2886%2B78%2B68%2B92%2B72%2BT%29%2F750%3C90