SOLUTION: Allowing 5% for waste, determine amount in feet of lead pipe 2 in. outer diameter, 1/4 in. thick from a ton of lead. A cu. ft. of lead weighs 710 lbs. / cu. ft.
A pipe is cons
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Allowing 5% for waste, determine amount in feet of lead pipe 2 in. outer diameter, 1/4 in. thick from a ton of lead. A cu. ft. of lead weighs 710 lbs. / cu. ft.
A pipe is cons
Log On
Question 1058956: Allowing 5% for waste, determine amount in feet of lead pipe 2 in. outer diameter, 1/4 in. thick from a ton of lead. A cu. ft. of lead weighs 710 lbs. / cu. ft.
A pipe is considered a cylinder.
.95 * 2000 = 1900 lbs. (amt. of material).
Area of circle; pi ^ r*2
Outer; 3.1416 * 1 * 1 = 3.1416 sq. in.
Inner; 3.1416 * .75 * .75 = 1.76 sq. in.
3.1416 - 1.76 = 1.38 sq. in. (area of end).
3.1416 * .39 * .39 * h = .4778h
Unsure from here. Thanks.
Non-homework.
You can put this solution on YOUR website! Allowing 5% for waste, determine amount in feet of lead pipe 2 in. outer diameter, 1/4 in. thick from a ton of lead. A cu. ft. of lead weighs 710 lbs. / cu. ft.
A pipe is considered a cylinder.
.95 * 2000 = 1900 lbs. (amt. of material).
Area of circle; pi ^ r*2
Outer; 3.1416 * 1 * 1 = 3.1416 sq. in.
Inner; 3.1416 * .75 * .75 = 1.76 sq. in.
3.1416 - 1.76 = 1.38 sq. in. (area of end).
3.1416 * .39 * .39 * h = .4778h
=======================
Cross-sectional area (CSA) = pi*(1^2 - 0.75^2) = 1.3745 sq inches
Volume of pipe = CSA*length
------
2000 lbs/710 lb/cu ft = 2.8169 cu ft of Pb
-5% = 0.95*2.8169 = 2.676 cu ft
2.676*12*12*12 = 4624.225 cu inches
-----
Vol of pipe = CSA*length
L = 4624.225/1.3745 =~ 3364.3 inches
=~ 280 feet
---
