Question 1058767: the sum of 3 integers is 246. the sum of of the first and second integers exceeds the third by 94. the third integer is 50 less than the first. find the three integer
Found 2 solutions by solve_for_x, jorel555:
Answer by solve_for_x(190)   (Show Source):
You can put this solution on YOUR website! Let x, y, and z represent the three integers.
Since the sum of the three integers is 246, we can write:
(1) x + y + z = 246
Then, since the sum of the first two is greater than the third by 94, we
can write:
(2) x + y = z + 94
And then, since the third integer is 50 less than the first, we can
write:
(3) x - 50 = z
Substituting x - 50 in place of x in (2) leaves:
x + y = (x - 50) + 94
x + y = x - 44
y = 44
Then, substituting x - 50 in place of z, and y = 44, in (1) gives:
x + 44 + x - 50 = 246
2x - 6 = 246
2x = 252
x = 126
Finally, the third integer is:
z = x - 50 = 126 - 50 = 76
Solution: The three integers are 126, 44, and 76
Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let the integers be m,n and p. Then:
m+n+p=246,
m+n-94=p, and
m-50=p
So
p+50+n-94=p
n=44;
m+p=202
m-p=50
2m=252
m=126
p=76
So m=126, n=44, and p=76. ☺☺☺☺
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