Question 1058594: The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 18 people reveals the mean yearly consumption to be 68 gallons with a standard deviation of 25 gallons. Assume that the population distribution is normal. (Use t Distribution Table.)
a. What is the value of the population mean?
A.) Unknown
B.) 68
C.) 25
b. What is the best estimate of this value?
Estimate population mean:
c. For a 95% confidence interval, what is the value of t? (Round your answer to 3 decimal places.)
Value of t:
d. Develop the 95% confidence interval for the population mean. (Round your answers to 3 decimal places.)
Confidence interval for the population mean is between and .
e. Would it be reasonable to conclude that the population mean is 55 gallons?
a.) Yes
b.) No
c.) It is not possible to tell.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 18 people reveals the mean yearly consumption to be 68 gallons with a standard deviation of 25 gallons. Assume that the population distribution is normal. (Use t Distribution Table.)
a.What is the value of the population mean?
Ans:: A
A.) Unknown
B.) 68
C.) 25
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b. What is the best estimate of this value?
Estimate population mean: point estimate = 68
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c. For a 95% confidence interval, what is the value of t? (Round your answer to 3 decimal places.)
Ans: t = invT(0.025,17) = 2.1098
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d. Develop the 95% confidence interval for the population mean. (Round your answers to 3 decimal places.)
sample mean::: 68
Margin of Error:: 2.1098*(25/sqrt(18)) = 12.43
Confidence interval for the population mean is
between 68-12.43 and 68+12.43 = (55.57,80.43)
e. Would it be reasonable to conclude that the population mean is 55 gallons?
a.) Yes
b.) No; it is not in the confidence interval
c.) It is not possible to tell.
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Cheers,
Stan H.
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