SOLUTION: 2x+6 = 3
----- ---
2x+8 4
8x = 3
--- -- then i flip these to and got
10x 4
8 divided by 4 = 2
10 divided by 2 = 5
answer I got was 2 over 5
Algebra ->
Equations
-> SOLUTION: 2x+6 = 3
----- ---
2x+8 4
8x = 3
--- -- then i flip these to and got
10x 4
8 divided by 4 = 2
10 divided by 2 = 5
answer I got was 2 over 5
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Question 1058538: 2x+6 = 3
----- ---
2x+8 4
8x = 3
--- -- then i flip these to and got
10x 4
8 divided by 4 = 2
10 divided by 2 = 5
answer I got was 2 over 5
and when you put the two equations as a list separated by a comma and use the SYSTEM tags, the display will be .
Now that the two equations are made clear, what you want with them is not told. Two equations in the same variable, both equated to . You can solve each but they may be totally separate equations, not likely a system. Your comment about "flipping" is imprecise.
Try solving your first equation. Use Multiplication Property of Equality, twice.
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(2x+6)/(2x+8)=3/4
You can put this solution on YOUR website!
2x+6 = 3
----- ---
2x+8 4
8x = 3
--- -- then i flip these to and got
10x 4
8 divided by 4 = 2
10 divided by 2 = 5
answer I got was 2 over 5
This is quite vague.
Anyway, if your equation is: , and you're trying to say that that reduces to , you couldn't be more WRONG!
FYI:
I think it's best to repost, but that time, make it less vague.