SOLUTION: Find the exact values of sin(&#952;/2), cos(&#952;/2), and tan(&#952;/2) for the given conditions. sec &#952; = &#8722;5/3; 180° < &#952; < 270°

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact values of sin(&#952;/2), cos(&#952;/2), and tan(&#952;/2) for the given conditions. sec &#952; = &#8722;5/3; 180° < &#952; < 270°      Log On


   



Question 1058519: Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given conditions.
sec θ = −5/3; 180° < θ < 270°

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given conditions.
sec θ = −5/3; 180° < θ < 270°
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Note:: cos(t) = -3/5
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sin(t/2) = sqrt[(1-cos(t))/2] = sqrt[8/10] = sqrt(0.4) = 0.6325
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cos(t/2) = sqrt[(1+cos(t))/2] = sqrt(0.2) = 0.4472
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tan(t/2) = sin(t/2)/cos(t/2) = 0.0001414..
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Cheers,
Stan H.