SOLUTION: Jane walked 4 miles her average speed was 3.2 miles per her. She spent 15 minutes longer on the last two miles than on the first two miles. how much did she spend on the first two

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Question 1058472: Jane walked 4 miles her average speed was 3.2 miles per her. She spent 15 minutes longer on the last two miles than on the first two miles. how much did she spend on the first two miles.
Found 3 solutions by josgarithmetic, josmiceli, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Fifteen minutes is same as %281%2F4%29hour. 
             RATE         TIME      DISTANCE
FIRST        2/t            t          2
LAST         2/(t+1/4)     t+1/4       2
AVERAGE      3.2
Total                    t+(t+1/4)     4


AVERAGE rate given as 3.2, and the rate for the average is the distance divided by the time; the TOTALS.

highlight%284%2F%28t%2B%28t%2B1%2F4%29%29=3.2%29

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+4+%2F+3.2+=+1.25+ hrs
Let +t+ = time spent on 1st 2 miles
+t+%2B+.25+ = time in hrs spent on last 2 miles
---------------------
+t+%2B+t+%2B+.25+=+1.25+
+2t+=+1.25+-+.25+
+2t+=+1+
+t+=+.5+
and
+t+%2B+.25+=+.75+
--------------------
She spent 1/2 hr on the 1st 2 miles


Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
Jane walked 4 miles her average speed was 3.2 miles per her. She spent 15 minutes longer on the last two miles
than on the first two miles. how much did she spend on the first two miles.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

1.  The total time spent for the walk is 4%2F3.2 = 1.25 hours = 1 1%2F4 hours.


2.  From 1 1%2F4 hours distract 15 min = 1%2F4 of an hour, and divide the result by 2.

    You will get 1%2F2 of an hour.
    It is the time Jane spent in the first two miles.

Answer. 1%2F2 of an hour.

Simple as a cucumber.