SOLUTION: Good day Will you please assist me with my homework. 1)The ages of three children in our family total 32 yeas. I'm twice as old as my sister, and my brother is 2 years older

Algebra ->  Absolute-value -> SOLUTION: Good day Will you please assist me with my homework. 1)The ages of three children in our family total 32 yeas. I'm twice as old as my sister, and my brother is 2 years older      Log On


   



Question 1058450: Good day
Will you please assist me with my homework.
1)The ages of three children in our family total 32 yeas. I'm twice as old as my sister, and my brother is 2 years older than I. how old am I?
2)given the expression below
3y^2-6+7y^3-y
2.1) what is the variable in the expression?
2.3)which is the constant term?
thank you
kind regards

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
1) let x be my age, y is my sister's age, z is my brother's age
:
x + y + z = 32
:
x = 2y and z = x + 2
:
also z = 2y + 2 (substitute for x)
:
therefore we have
:
2y + y + (2y + 2) = 32
:
5y + 2 = 32
:
5y = 30
:
y = 6
:
*************************
I am 6 * 2 = 12 years old
*************************
:
2.1) variable is y
:
2.3) constant term is -6
: