SOLUTION: Bill buys 200 bags of oranges at $28 per bag. There are 60 oranges in each bag. 15% of the oranges are rotten. Find the selling price per orange if he wants to earn an 80% profit o

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: Bill buys 200 bags of oranges at $28 per bag. There are 60 oranges in each bag. 15% of the oranges are rotten. Find the selling price per orange if he wants to earn an 80% profit o      Log On


   



Question 1058433: Bill buys 200 bags of oranges at $28 per bag. There are 60 oranges in each bag. 15% of the oranges are rotten. Find the selling price per orange if he wants to earn an 80% profit on the cost price.
Found 3 solutions by josgarithmetic, MathTherapy, jonforall:
Answer by josgarithmetic(39623) About Me  (Show Source):
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200 bags, 28 dollars/bag, 60 oranges per bag, only 85% are good oranges.

COST: 200%2A28=5600%2Adollars
Quantity Oranges bought: 200%2A60=12000%2Aoranges
Quantity GOOD oranges bought: %280.85%29%2812000%29=9840%2AgoodOranges

PROFIT EXPECTED: 80%;
Let p be price per orange for Bill to sell the good oranges;
%281.8%29%285600%29=p%2A9840
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highlight%28p=%281.8%29%285600%29%2F9840%29


Compute p.
Put in the units to be sure the expressions used in the steps make sense.
p=1.024%28dollars%2Forange%29

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Bill buys 200 bags of oranges at $28 per bag. There are 60 oranges in each bag. 15% of the oranges are rotten. Find the selling price per orange if he wants to earn an 80% profit on the cost price.
Selling price of each orange in order to make an 80% profit: highlight_green%28matrix%281%2C4%2C+0.988235294%2C+or%2C+about%2C+%22%240.99%22%29%29
All other answers are INCORRECT!!

Answer by jonforall(1) About Me  (Show Source):
You can put this solution on YOUR website!
Thanks. I've just found an answer after using your good oranges: 85%. Only my final result is different. Mine is $0.99. Because 0.85 times 12000 is 10200. So cost price for one orange is 5600/10200 = $0.55. Then selling price should be $0
55+(0.8 times 0.55) = $0.99. Thanks anyway for telling me to use number of good oranges is 85%, this led me to my final result.