|  | 
| 
 
 
| Question 1058425:  Total profit P is the difference between total revenue R and total cost C. Given the following total-revenue and total-cost functions, find the total profit, the maximum value of the total profit, and the value of x at which it occurs..
 R(x)= 1200x-(x squared)
 C(x)= 3100+20x
 Answer by solve_for_x(190)
      (Show Source): 
You can put this solution on YOUR website! The profit function is: 
 P(x) = R(x) - C(x)
 
 P(x) = (1200x - x^2) - (3100 + 20x)
 
 P(x) = -x^2 + 1200x - 20x - 3100
 
 P(x) = -x^2 + 1180x - 3100
 
 This is the equation of a parabola that opens downward. The maximum value of the profit
 corresponds to the vertex of the parabola.
 
 The x-coordinate of the vertex is:
 
 x = -b/2a = (-1180) / (-1*2) = 590
 
 The function value at the vertex is then:
 
 P(590) = -(590)^2 + 1198(590) - 3100
 
 P(590) = 345,000
 
 Solution:
 
 Total profit = -x^2 + 1180x - 3100
 
 Maximum profit = 345,000, at x = 590
 | 
  
 | 
 |  |  |