SOLUTION: Can you help with this please. Show the steps that you would use to solve the following 5-2/x-6=10-2x/x-6 Second part to this why isthis not a solution. My solution

Algebra ->  Equations -> SOLUTION: Can you help with this please. Show the steps that you would use to solve the following 5-2/x-6=10-2x/x-6 Second part to this why isthis not a solution. My solution       Log On


   

Question 105831: Can you help with this please.
Show the steps that you would use to solve the following
5-2/x-6=10-2x/x-6
Second part to this why isthis not a solution.
My solution
5=10-2x/x-6+2/x-6
5=12-2x/2x-12
5=0

Thank You
Found 2 solutions by Fombitz, checkley75:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
5-2%2F%28x-6%29=10-2x%2F%28x-6%29
5=10-2x%2F%28x-6%29%2B2%2F%28x-6%29
5=highlight%2812%29-highlight%282x%2F%282x-12%29%29
The highlighted boxes show where you made your mistakes.
First off, in the second line, you have 10, where did the 12 come from in line 3.
Second, when you add fractions, you need to have the same denominator. Then you can add or subtract the numerators keeping the same denominator.
A%2FC%2BB%2FC=%28A%2BB%29%2FC
You added denominators.
Let's go back to your second line.
5=10-2x%2F%28x-6%29%2B2%2F%28x-6%29
5=10%2B%282-2x%29%2F%28x-6%29
I'll leave you there. I think you can proceed from here.
Move that 10 from the right hand side (additive inverse).
Multiply both sides by the denominator (x-6) and then solve for x.
Good luck. If you get stuck post another question.

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
5-2/(x-6)=10-2x/(x-6)
if this is the problem? then:
-2/(x-6)+2x/(x-6)=10-5
(-2+2x)/(x-6)=5 now cross multiply.
-2+2x=5x-30
2x-5x=-30+2
-3x=-28
x=28/3 answer.
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or
5-(2/x)-6=10-(2x/x)-6
5-2/x-6=10-2-6
-2/x=10-2-6-5+6
-2/x=3
x=3/-2
x=-3/2 answer.