SOLUTION: mark and linda had 90 sweets altogether. after mark ate 1/3 of his sweets and linda ate 25 sweets. they had an equal number of sweet left. how many sweet did each of them have at f

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: mark and linda had 90 sweets altogether. after mark ate 1/3 of his sweets and linda ate 25 sweets. they had an equal number of sweet left. how many sweet did each of them have at f      Log On


   

Question 1058252: mark and linda had 90 sweets altogether. after mark ate 1/3 of his sweets and linda ate 25 sweets. they had an equal number of sweet left. how many sweet did each of them have at first?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
mark and linda had 90 sweets altogether. after mark ate 1/3 of his sweets and linda ate 25 sweets. they had an equal number of sweet left. how many sweet did each of them have at first?
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Start::
Mark had x
Linda had 90-x
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Change::
Mark had (2/3)x
Linda had 90-x-25 = 65-x
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Equation:
(2/3)x = 65-x
2x = 195 - 3x
5x = 195
x = 39 (Mark had originally)
90-x = 51 (Linda had originally)
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Cheers,
Stan H.
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