SOLUTION: z varies directly as x^3 and inversely as y^3. If z = 184 when x = 10 and y = 6, find z if x = 9 and y = 3. (Round off your answer to the nearest hundredth.)

Algebra ->  Absolute-value -> SOLUTION: z varies directly as x^3 and inversely as y^3. If z = 184 when x = 10 and y = 6, find z if x = 9 and y = 3. (Round off your answer to the nearest hundredth.)       Log On


   



Question 1058213: z varies directly as x^3 and inversely as y^3.
If z = 184 when x = 10 and y = 6,
find z if x = 9 and y = 3.
(Round off your answer to the nearest hundredth.)

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
z varies directly as x^3 and inversely as y^3.
If z = 184 when x = 10 and y = 6,
find z if x = 9 and y = 3.
(Round off your answer to the nearest hundredth.)



Formula:
                       
                       "directly" variable (or product of "jointly" variables)
                         (if no directly or jointly variables, write 1 here)
"Varying" quantity = k·---------------------------------------------------------
                      "inversely" variable (or product of "inversely variables")
                        (If no inversely variable(s), write 1 here)

The "varying" quantity is z.
There is one "directly" variable, x³
There is one "inversely" variable, y³

Substituting
                      x³
               z = k·----
                      y³

Substituting the complete set of data, 
where ALL the variables are given:

z=184, x=10, y=6


                      10³
             184 = k·-----
                      6³

                      1000
             184 = k·-----
                       216

Reduce 1000/216 to 125/27

                      125
             184 = k·-----
                       27

Solve for k. Multiply through by 27

                      
            4968 = k·125
                      
            4968
            ---- = k
             125 
             
                       

Now substitute k = 4968/125 into:

                      x³
               z = k·----
                      y³

which gives:

                   4968  x³ 
               z = ----·----
                    125  y³
                      

Now substitute the second set of data,
and solve for the missing letter z

Substitute x=9 and y=3 into

                   4968  x³ 
               z = ----·----
                    125  y³

                   4968  9³ 
               z = ----·----
                    125  3³

We grab the calculator and get
                           
               z = 1073.088

Round to the nearest hundredth:

               z = 1073.09

Edwin