SOLUTION: Find three consecutive odd natural numbers such that the product of the first and the last is 11 greater than two times the middle one.

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Question 1058067: Find three consecutive odd natural numbers such that the product of the first and the last is 11 greater than two times the middle one.
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be the first odd number. Then the next numbers in sequence will be n+2 and n+4. So:
n(n+4)=2(n+2)+11
nē+4n=2n+15
nē+2n-15=0
(n+5)(n-3)=0
n=3 or -5
Throwing out the negative answer, we get the consecutive odd numbers as 3, 5, and 7. ☺☺☺☺