Question 1058027: Father is 16 years older than his son. 6 years ago the father was 3 times his sons age. How are are both the son and his father now?
Answer by solve_for_x(190)   (Show Source):
You can put this solution on YOUR website! Let x represent the son's age.
The father's current age is then x + 16.
Six years ago, the father's age was (x + 16) - 6 = x + 10.
Six years ago, the son's age was x - 6.
Since the father's age then was 3 times the son's age you can write the following equation:
x + 10 = 3(x - 6)
x + 10 = 3x - 18
3x - 18 = x + 10
3x - x - 18 = 10
2x - 18 = 10
2x = 10 + 18
2x = 28
x = 14
Thus, the son's current age is 14, and the father's current age is 14 + 16 = 30.
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