SOLUTION: 2^x = 3^(x - 1) + 5^(-x)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 2^x = 3^(x - 1) + 5^(-x)      Log On


   

Question 1058009: 2^x = 3^(x - 1) + 5^(-x)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2 solutions by graphical methods.
---
x =~ 0.19426166396863
x =~ 2.704637828038605