SOLUTION: An initial survey was performed right after Médecins Sans Frontières accused my brother of wrong doing. Of 1852 customers, 53 were against the aggressive tactics of Médecins Sans
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-> SOLUTION: An initial survey was performed right after Médecins Sans Frontières accused my brother of wrong doing. Of 1852 customers, 53 were against the aggressive tactics of Médecins Sans
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Question 1057902: An initial survey was performed right after Médecins Sans Frontières accused my brother of wrong doing. Of 1852 customers, 53 were against the aggressive tactics of Médecins Sans Frontières. After my brother was cleared by the court, a follow-up survey was performed. Of 4699 customers, 1751 said they did not agree with the aggressive tactics of Médecins Sans Frontières.
At the 1% significance level, do the data suggest that a higher percentage of customers were against Médecins Sans Frontières after the court case?
You can put this solution on YOUR website! The proportion of interest is 53/1852=0.0286
The new proportion is 1751/4699=0.3726
Ho=no difference
Ha=difference
alpha=0.01
1 sample proportion looking at 0.0286
use a z(0.995)2-tailed with critical value |z|>2.576
z=(0.3726-0.0286)/sqrt {(.0286)(0.9714)/4699}; std error=0.00243
z=(0.3440)/0.00243=141.56
Strongly reject Ho and high likelihood that there is a higher percentage of customers who were against them.
