SOLUTION: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.

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Question 105785: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
2L+2W=PERIMETER.
L=3W+8
2(3W+8)+2W=64
6W+16+2W=64
8W=64-16
8W=48
W=48/8
W=6CM FOR THE WIDTH.
L=3*6+8
L=18+8
L=26 CM FOR THE LENGTH.
PROOF
2*26+2*6=64
52+12=64
64=64