Question 1057810: Given the numbers 3,6,10,5, which groups of 3 of these numbers can be
the three sides of a triangle, using the Triangle Inequality Theorem.
Answer by Edwin McCravy(20060) (Show Source):
You can put this solution on YOUR website! Given the numbers 3,6,10,5, which groups of 3 of these numbers can be
the three sides of a triangle, using the Triangle Inequality Theorem.
The triangle inequality theorem states that the sum of any two sides
of a triangle is always greater than the third side.
There are four groups of three of the numbers 3,6,10,5.
3,6,10 <-- These cannot be the three sides of a triangle
because 3+6 < 10 and the sum of any two sides must
be greater than the third side.
3,6,5 <--These can be the three sides of a triangle because
3+6 > 5, 3+5 > 6, and 6+5 > 3
3,10,5 <-- These cannot be the three sides of a triangle
because 3+5 < 10 and the sum of any two sides must
be greater than the third side.
6,10,5 <--These can be the three sides of a triangle because
6+10 > 16, 6+5 > 11, and 10+5 > 6
Edwin
|
|
|