SOLUTION: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. 5 7 17 34

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Question 105768: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
5
7
17
34
Found 3 solutions by joLeeBee08, kmcruz09, jermz69:
Answer by joLeeBee08(3) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the smaller no.
thus, x+12 be the larger number.
The sum of the smaller number and twice the larger number is 39.
therefore the eworking equation should be: x+2(x+12)=39 >>> x+2x+24=39 >>>
3x=39-24 >>> 3x=15 >>> x=5
Take note that x is the smaller no. and the bigger no. is x+12 or 5+12 or
17

Answer by kmcruz09(38) About Me  (Show Source):
You can put this solution on YOUR website!
One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
5
7
17
34
Let x = first number
then x + 12 = larger number
x%2B2%28x%2B12%29=39
Solving, we have:
x%2B2x%2B24=39
3x+=+15
x=5
x+%2B+12+=+5+%2B+12+=+17
Therefore, the numbers are 5 and 17, the larger number is 17.
Thank you.
~kmcruz09~

Answer by jermz69(5) About Me  (Show Source):
You can put this solution on YOUR website!
One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
5
7
17
34

Let x: smaller number
x+12: larger number

Equation: x + 2(x+12) = 39
x + 2x + 24 = 39
3x + 24 = 39
3x = 39 - 24
3x = 15
3x/3 = 15/3
x = 5

Larger number: x + 12
5 + 12
17

By the way, this is jermz69.