SOLUTION: The sum of the second and third terms of a geometric progression is six times the fourth term. Find the two possible values of the common ratio.
Algebra ->
Triangles
-> SOLUTION: The sum of the second and third terms of a geometric progression is six times the fourth term. Find the two possible values of the common ratio.
Log On
Question 1057668: The sum of the second and third terms of a geometric progression is six times the fourth term. Find the two possible values of the common ratio. Answer by ikleyn(52798) (Show Source):
You can put this solution on YOUR website! .
The sum of the second and third terms of a geometric progression is six times the fourth term.
Find the two possible values of the common ratio.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The condition says
=
where "a" is the first term and "r" is the common ratio.
It leads to the equation
= 0, or, in the factorized form
(2r-1)*(3r+1) = 0.
The roots are and .
It is your answer.
