SOLUTION: the sum of two integers is 64. one integer is 20 less than twice the other. find the smaller integer.
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Question 1057221
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the sum of two integers is 64. one integer is 20 less than twice the other. find the smaller integer.
Answer by
addingup(3677)
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x+y = 64
x = 2y-20
2y-20+y = 64
3y = 84
y = 28 this is y, and x:
x = 2y-20 = 2(28)-20 = 56-20 = 36
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Check:
28+36 = 64 Correct
:
john