SOLUTION: ten times smallest of three consicutive integers is 22 more than 3 times the sum of integers.find the integers?

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Question 1057194: ten times smallest of three consicutive integers is 22 more than 3 times the sum of integers.find the integers?
Answer by math_helper(2461) About Me  (Show Source):
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Let n be the smallest integer
Then n+1 and n+2 represent the next two consecutive integers.
10n = 22+3(n+(n+1)+(n+2)) "10 times the smallest is 22 more than 3 times the sum of integers"
10n = 22+3(3n+3)
10n = 22+9n+9
n = 31
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Ans: The integers are 31, 32, and 33
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Check:
10 * 31 = 310
22+3(31+32+33) = 310 (ok)