SOLUTION: A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 4 mph. Find
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Question 1057033: A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 4 mph. Find the rate of the rowing team in Stillwater. Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let s be the rate of the team in still water. Then:
90/s+4=10/s-4
90s-360=10s+40
80s=400
s=5
The rate of the team in still water is 5 mph. ☺☺☺☺