SOLUTION: A long distance runner start at the beginning of a trail and runs at a rate of 6 mph. Two hours later, a cyclist starts at the beginning of the trail and travels at a rate of 16 m

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A long distance runner start at the beginning of a trail and runs at a rate of 6 mph. Two hours later, a cyclist starts at the beginning of the trail and travels at a rate of 16 m      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1056992: A long distance runner start at the beginning of a trail and runs at a rate of 6 mph. Two hours later, a cyclist starts at the beginning of the trail and travels at a rate of 16 mph. What is the amount of time that the cyclist travels before overtaking the runner?
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
A long distance runner start at the beginning of a trail and runs at a rate of 6 mph. Two hours later, a cyclist starts at the beginning
of the trail and travels at a rate of 16 mph. What is the amount of time that the cyclist travels before overtaking the runner?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

%282%2A6%29%2F%2816-6%29 = 12%2F10 = 1 2%2F10 hours = 2 hours 12 minutes.


2*6 in the numerator is the distance (in miles) the runner was ahead the cyclist at the moment cyclist started his move.

16 - 6 = 10 mph is their relative speed.

For introductory lesson on Travel and Distance see
    - Travel and Distance problems